(25b-1)-8(3b+2)=-6

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Solution for (25b-1)-8(3b+2)=-6 equation:



(25b-1)-8(3b+2)=-6
We move all terms to the left:
(25b-1)-8(3b+2)-(-6)=0
We add all the numbers together, and all the variables
(25b-1)-8(3b+2)+6=0
We multiply parentheses
(25b-1)-24b-16+6=0
We get rid of parentheses
25b-24b-1-16+6=0
We add all the numbers together, and all the variables
b-11=0
We move all terms containing b to the left, all other terms to the right
b=11

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