(25b-2)-8(3b+4)=-7

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Solution for (25b-2)-8(3b+4)=-7 equation: 



(25b-2)-8(3b+4)=-7

We move all terms to the left:

(25b-2)-8(3b+4)-(-7)=0

We add all the numbers together, and all the variables

(25b-2)-8(3b+4)+7=0

We multiply parentheses

(25b-2)-24b-32+7=0

We get rid of parentheses

25b-24b-2-32+7=0

We add all the numbers together, and all the variables

b-27=0

We move all terms containing b to the left, all other terms to the right

b=27

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