(25m2-20m+4)/(5m-2)

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Solution for (25m2-20m+4)/(5m-2) equation: 


D( m )

5*m-2 = 0

5*m-2 = 0

5*m-2 = 0

5*m-2 = 0 // + 2

5*m = 2 // : 5

m = 2/5

m in (-oo:2/5) U (2/5:+oo)

(25*m^2-(20*m)+4)/(5*m-2) = 0

(25*m^2-20*m+4)/(5*m-2) = 0

25*m^2-20*m+4 = 0

25*m^2-20*m+4 = 0

DELTA = (-20)^2-(4*4*25)

DELTA = 0

m = 20/(2*25)

m = 2/5 or m = 2/5

(m-2/5)^2 = 0

((m-2/5)^2)/(5*m-2) = 0

m-2/5 = 0 // + 2/5

m = 2/5

m in { 2/5} 

m belongs to the empty set

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