(26-2x)(8-2x)=88

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Solution for (26-2x)(8-2x)=88 equation:



(26-2x)(8-2x)=88
We move all terms to the left:
(26-2x)(8-2x)-(88)=0
We add all the numbers together, and all the variables
(-2x+26)(-2x+8)-88=0
We multiply parentheses ..
(+4x^2-16x-52x+208)-88=0
We get rid of parentheses
4x^2-16x-52x+208-88=0
We add all the numbers together, and all the variables
4x^2-68x+120=0
a = 4; b = -68; c = +120;
Δ = b2-4ac
Δ = -682-4·4·120
Δ = 2704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2704}=52$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-68)-52}{2*4}=\frac{16}{8} =2 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-68)+52}{2*4}=\frac{120}{8} =15 $

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