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(260-2x)*x=x
We move all terms to the left:
(260-2x)*x-(x)=0
We add all the numbers together, and all the variables
(-2x+260)*x-x=0
We add all the numbers together, and all the variables
-1x+(-2x+260)*x=0
We multiply parentheses
-2x^2-1x+260x=0
We add all the numbers together, and all the variables
-2x^2+259x=0
a = -2; b = 259; c = 0;
Δ = b2-4ac
Δ = 2592-4·(-2)·0
Δ = 67081
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{67081}=259$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(259)-259}{2*-2}=\frac{-518}{-4} =129+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(259)+259}{2*-2}=\frac{0}{-4} =0 $
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