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(26x-7)(10x+7)=x
We move all terms to the left:
(26x-7)(10x+7)-(x)=0
We add all the numbers together, and all the variables
-1x+(26x-7)(10x+7)=0
We multiply parentheses ..
(+260x^2+182x-70x-49)-1x=0
We get rid of parentheses
260x^2+182x-70x-1x-49=0
We add all the numbers together, and all the variables
260x^2+111x-49=0
a = 260; b = 111; c = -49;
Δ = b2-4ac
Δ = 1112-4·260·(-49)
Δ = 63281
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(111)-\sqrt{63281}}{2*260}=\frac{-111-\sqrt{63281}}{520} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(111)+\sqrt{63281}}{2*260}=\frac{-111+\sqrt{63281}}{520} $
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