(27+d)/4=(3+d)

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Solution for (27+d)/4=(3+d) equation: 


d in (-oo:+oo)

(d+27)/4 = d+3 // - d+3

(d+27)/4-d-3 = 0

(d+27)/4+(4*(-d))/4+(-3*4)/4 = 0

d+4*(-d)-3*4+27 = 0

27-3*d-12 = 0

15-3*d = 0

(15-3*d)/4 = 0

(15-3*d)/4 = 0 // * 4

15-3*d = 0

15-3*d = 0 // - 15

-3*d = -15 // : -3

d = -15/(-3)

d = 5

d = 5

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