(27+x)+10=(3x+47)+(x+26)

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Solution for (27+x)+10=(3x+47)+(x+26) equation: 



(27+x)+10=(3x+47)+(x+26)

We move all terms to the left:

(27+x)+10-((3x+47)+(x+26))=0

We add all the numbers together, and all the variables

(x+27)-((3x+47)+(x+26))+10=0

We get rid of parentheses

x-((3x+47)+(x+26))+27+10=0



We calculate terms in parentheses: -((3x+47)+(x+26)), so:

(3x+47)+(x+26)

We get rid of parentheses

3x+x+47+26

We add all the numbers together, and all the variables

4x+73

Back to the equation:

-(4x+73)



We add all the numbers together, and all the variables

x-(4x+73)+37=0

We get rid of parentheses

x-4x-73+37=0

We add all the numbers together, and all the variables

-3x-36=0

We move all terms containing x to the left, all other terms to the right

-3x=36

x=36/-3

x=-12

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