(27/9x)+x=4

Solution for (27/9x)+x=4 equation:

(27/9x)+x=4

We move all terms to the left:

(27/9x)+x-(4)=0


Domain of the equation: 9x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+27/9x)+x-4=0

We add all the numbers together, and all the variables

x+(+27/9x)-4=0

We get rid of parentheses

x+27/9x-4=0

We multiply all the terms by the denominator


x*9x-4*9x+27=0

Wy multiply elements

9x^2-36x+27=0

a = 9; b = -36; c = +27;
Δ = b2-4ac
Δ = -362-4·9·27
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-18}{2*9}=\frac{18}{18}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+18}{2*9}=\frac{54}{18}
=3
$