(27x+3-9x-5)/2=(10x-2)

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Solution for (27x+3-9x-5)/2=(10x-2) equation:



(27x+3-9x-5)/2=(10x-2)
We move all terms to the left:
(27x+3-9x-5)/2-((10x-2))=0
We add all the numbers together, and all the variables
(18x-2)/2-((10x-2))=0
We multiply all the terms by the denominator
(18x-2)-(((10x-2)))*2=0
We get rid of parentheses
18x-(((10x-2)))*2-2=0
We move all terms containing x to the left, all other terms to the right
18x-(((10x-2)))*2=2

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