(27x+3-9x-5)=(10x-2)

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Solution for (27x+3-9x-5)=(10x-2) equation: 



(27x+3-9x-5)=(10x-2)

We move all terms to the left:

(27x+3-9x-5)-((10x-2))=0

We add all the numbers together, and all the variables

(18x-2)-((10x-2))=0

We get rid of parentheses

18x-((10x-2))-2=0



We calculate terms in parentheses: -((10x-2)), so:

(10x-2)

We get rid of parentheses

10x-2

Back to the equation:

-(10x-2)



We get rid of parentheses

18x-10x+2-2=0

We add all the numbers together, and all the variables

8x=0

x=0/8

x=0

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