(28-6x)-(2-2x)=3(2x-25)

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Solution for (28-6x)-(2-2x)=3(2x-25) equation: 



(28-6x)-(2-2x)=3(2x-25)

We move all terms to the left:

(28-6x)-(2-2x)-(3(2x-25))=0

We add all the numbers together, and all the variables

(-6x+28)-(-2x+2)-(3(2x-25))=0

We get rid of parentheses

-6x+2x-(3(2x-25))+28-2=0



We calculate terms in parentheses: -(3(2x-25)), so:

3(2x-25)

We multiply parentheses

6x-75

Back to the equation:

-(6x-75)



We add all the numbers together, and all the variables

-4x-(6x-75)+26=0

We get rid of parentheses

-4x-6x+75+26=0

We add all the numbers together, and all the variables

-10x+101=0

We move all terms containing x to the left, all other terms to the right

-10x=-101

x=-101/-10

x=10+1/10

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