(28-x)(20-x)=(37-x)(26-x)

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Solution for (28-x)(20-x)=(37-x)(26-x) equation:



(28-x)(20-x)=(37-x)(26-x)
We move all terms to the left:
(28-x)(20-x)-((37-x)(26-x))=0
We add all the numbers together, and all the variables
(-1x+28)(-1x+20)-((-1x+37)(-1x+26))=0
We multiply parentheses ..
(+x^2-20x-28x+560)-((-1x+37)(-1x+26))=0
We calculate terms in parentheses: -((-1x+37)(-1x+26)), so:
(-1x+37)(-1x+26)
We multiply parentheses ..
(+x^2-26x-37x+962)
We get rid of parentheses
x^2-26x-37x+962
We add all the numbers together, and all the variables
x^2-63x+962
Back to the equation:
-(x^2-63x+962)
We get rid of parentheses
x^2-x^2-20x-28x+63x+560-962=0
We add all the numbers together, and all the variables
15x-402=0
We move all terms containing x to the left, all other terms to the right
15x=402
x=402/15
x=26+4/5

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