(28-x)(26-x)=(20-x)(37-x)

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Solution for (28-x)(26-x)=(20-x)(37-x) equation: 



(28-x)(26-x)=(20-x)(37-x)

We move all terms to the left:

(28-x)(26-x)-((20-x)(37-x))=0

We add all the numbers together, and all the variables

(-1x+28)(-1x+26)-((-1x+20)(-1x+37))=0

We multiply parentheses ..

(+x^2-26x-28x+728)-((-1x+20)(-1x+37))=0



We calculate terms in parentheses: -((-1x+20)(-1x+37)), so:

(-1x+20)(-1x+37)

We multiply parentheses ..

(+x^2-37x-20x+740)

We get rid of parentheses

x^2-37x-20x+740

We add all the numbers together, and all the variables

x^2-57x+740

Back to the equation:

-(x^2-57x+740)



We get rid of parentheses

x^2-x^2-26x-28x+57x+728-740=0

We add all the numbers together, and all the variables

3x-12=0

We move all terms containing x to the left, all other terms to the right

3x=12

x=12/3

x=4

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