(28b-3)-9(3b+3)=2

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Solution for (28b-3)-9(3b+3)=2 equation:


Simplifying
(28b + -3) + -9(3b + 3) = 2

Reorder the terms:
(-3 + 28b) + -9(3b + 3) = 2

Remove parenthesis around (-3 + 28b)
-3 + 28b + -9(3b + 3) = 2

Reorder the terms:
-3 + 28b + -9(3 + 3b) = 2
-3 + 28b + (3 * -9 + 3b * -9) = 2
-3 + 28b + (-27 + -27b) = 2

Reorder the terms:
-3 + -27 + 28b + -27b = 2

Combine like terms: -3 + -27 = -30
-30 + 28b + -27b = 2

Combine like terms: 28b + -27b = 1b
-30 + 1b = 2

Solving
-30 + 1b = 2

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '30' to each side of the equation.
-30 + 30 + 1b = 2 + 30

Combine like terms: -30 + 30 = 0
0 + 1b = 2 + 30
1b = 2 + 30

Combine like terms: 2 + 30 = 32
1b = 32

Divide each side by '1'.
b = 32

Simplifying
b = 32

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