(29-2x)=3(3x+2)

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Solution for (29-2x)=3(3x+2) equation: 



(29-2x)=3(3x+2)

We move all terms to the left:

(29-2x)-(3(3x+2))=0

We add all the numbers together, and all the variables

(-2x+29)-(3(3x+2))=0

We get rid of parentheses

-2x-(3(3x+2))+29=0



We calculate terms in parentheses: -(3(3x+2)), so:

3(3x+2)

We multiply parentheses

9x+6

Back to the equation:

-(9x+6)



We get rid of parentheses

-2x-9x-6+29=0

We add all the numbers together, and all the variables

-11x+23=0

We move all terms containing x to the left, all other terms to the right

-11x=-23

x=-23/-11

x=2+1/11

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