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(29x+-3)=(15x+7)
We move all terms to the left:
(29x+-3)-((15x+7))=0
We add all the numbers together, and all the variables
(29x-3)-((15x+7))=0
We get rid of parentheses
29x-((15x+7))-3=0
We calculate terms in parentheses: -((15x+7)), so:We get rid of parentheses
(15x+7)
We get rid of parentheses
15x+7
Back to the equation:
-(15x+7)
29x-15x-7-3=0
We add all the numbers together, and all the variables
14x-10=0
We move all terms containing x to the left, all other terms to the right
14x=10
x=10/14
x=5/7
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