(29x-3)=(19x+12)+7x

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Solution for (29x-3)=(19x+12)+7x equation: 



(29x-3)=(19x+12)+7x

We move all terms to the left:

(29x-3)-((19x+12)+7x)=0

We get rid of parentheses

29x-((19x+12)+7x)-3=0



We calculate terms in parentheses: -((19x+12)+7x), so:

(19x+12)+7x

We add all the numbers together, and all the variables

7x+(19x+12)

We get rid of parentheses

7x+19x+12

We add all the numbers together, and all the variables

26x+12

Back to the equation:

-(26x+12)



We get rid of parentheses

29x-26x-12-3=0

We add all the numbers together, and all the variables

3x-15=0

We move all terms containing x to the left, all other terms to the right

3x=15

x=15/3

x=5

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