(2C-1)/(5x-2)=15/3x

Solution for (2C-1)/(5x-2)=15/3x equation:

(2-1)/(5C-2)=15/3C

We move all terms to the left:

(2-1)/(5C-2)-(15/3C)=0


Domain of the equation: (5C-2)!=0

We move all terms containing C to the left, all other terms to the right

5C!=2

C!=2/5

C!=2/5

C∈R



Domain of the equation: 3C)!=0

C!=0/1

C!=0

C∈R


We add all the numbers together, and all the variables

1/(5C-2)-(+15/3C)=0

We get rid of parentheses

1/(5C-2)-15/3C=0

We calculate fractions


3C/(15C^2-6C)+(-75C+30)/(15C^2-6C)=0

We multiply all the terms by the denominator


3C+(-75C+30)=0

We get rid of parentheses

3C-75C+30=0

We add all the numbers together, and all the variables

-72C+30=0

We move all terms containing C to the left, all other terms to the right

-72C=-30

C=-30/-72

C=5/12