(2R-1)/5=(1-2R)2

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Solution for (2R-1)/5=(1-2R)2 equation: 


R in (-oo:+oo)

(2*R-1)/5 = (1-(2*R))^2 // - (1-(2*R))^2

(2*R-1)/5-(1-(2*R))^2 = 0

(2*R-1)/5-(1-2*R)^2 = 0

(2*R-1)/5-1*(1-2*R)^2 = 0

(2*R-1)/5+(-1*5*(1-2*R)^2)/5 = 0

2*R-1*5*(1-2*R)^2-1 = 0

22*R-20*R^2-6 = 0

22*R-20*R^2-6 = 0

2*(11*R-10*R^2-3) = 0

11*R-10*R^2-3 = 0

DELTA = 11^2-(-10*(-3)*4)

DELTA = 1

DELTA > 0

R = (1^(1/2)-11)/(-10*2) or R = (-1^(1/2)-11)/(-10*2)

R = 1/2 or R = 3/5

2*(R-1/2)*(R-3/5) = 0

(2*(R-1/2)*(R-3/5))/5 = 0

(2*(R-1/2)*(R-3/5))/5 = 0 // * 5

2*(R-1/2)*(R-3/5) = 0

( 2 )

2 = 0

R belongs to the empty set

( R-1/2 )

R-1/2 = 0 // + 1/2

R = 1/2

( R-3/5 )

R-3/5 = 0 // + 3/5

R = 3/5

R in { 1/2, 3/5 }

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