(2X+1)(2x+2)=132

Solution for (2X+1)(2x+2)=132 equation:

(2X+1)(2X+2)=132

We move all terms to the left:

(2X+1)(2X+2)-(132)=0

We multiply parentheses ..

(+4X^2+4X+2X+2)-132=0

We get rid of parentheses

4X^2+4X+2X+2-132=0

We add all the numbers together, and all the variables

4X^2+6X-130=0

a = 4; b = 6; c = -130;
Δ = b2-4ac
Δ = 62-4·4·(-130)
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2116}=46$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-46}{2*4}=\frac{-52}{8}
=-6+1/2
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+46}{2*4}=\frac{40}{8}
=5
$