(2X-2)(X+1)+5=7

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Solution for (2X-2)(X+1)+5=7 equation: 


Simplifying
(2X + -2)(X + 1) + 5 = 7

Reorder the terms:
(-2 + 2X)(X + 1) + 5 = 7

Reorder the terms:
(-2 + 2X)(1 + X) + 5 = 7

Multiply (-2 + 2X) * (1 + X)
(-2(1 + X) + 2X * (1 + X)) + 5 = 7
((1 * -2 + X * -2) + 2X * (1 + X)) + 5 = 7
((-2 + -2X) + 2X * (1 + X)) + 5 = 7
(-2 + -2X + (1 * 2X + X * 2X)) + 5 = 7
(-2 + -2X + (2X + 2X2)) + 5 = 7

Combine like terms: -2X + 2X = 0
(-2 + 0 + 2X2) + 5 = 7
(-2 + 2X2) + 5 = 7

Reorder the terms:
-2 + 5 + 2X2 = 7

Combine like terms: -2 + 5 = 3
3 + 2X2 = 7

Solving
3 + 2X2 = 7

Solving for variable 'X'.

Move all terms containing X to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 2X2 = 7 + -3

Combine like terms: 3 + -3 = 0
0 + 2X2 = 7 + -3
2X2 = 7 + -3

Combine like terms: 7 + -3 = 4
2X2 = 4

Divide each side by '2'.
X2 = 2

Simplifying
X2 = 2

Take the square root of each side:
X = {-1.414213562, 1.414213562}

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