(2X-5)(7x-3)=0

Solution for (2X-5)(7x-3)=0 equation:

(2X-5)(7X-3)=0

We multiply parentheses ..

(+14X^2-6X-35X+15)=0

We get rid of parentheses

14X^2-6X-35X+15=0

We add all the numbers together, and all the variables

14X^2-41X+15=0

a = 14; b = -41; c = +15;
Δ = b2-4ac
Δ = -412-4·14·15
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-41)-29}{2*14}=\frac{12}{28}
=3/7
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-41)+29}{2*14}=\frac{70}{28}
=2+1/2
$