(2a+3)*(3a-2)=0

Solution for (2a+3)*(3a-2)=0 equation:

(2a+3)(3a-2)=0

We multiply parentheses ..

(+6a^2-4a+9a-6)=0

We get rid of parentheses

6a^2-4a+9a-6=0

We add all the numbers together, and all the variables

6a^2+5a-6=0

a = 6; b = 5; c = -6;
Δ = b2-4ac
Δ = 52-4·6·(-6)
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-13}{2*6}=\frac{-18}{12}
=-1+1/2
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+13}{2*6}=\frac{8}{12}
=2/3
$