(2a+3)-(1-3a)-4a=3a

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Solution for (2a+3)-(1-3a)-4a=3a equation: 



(2a+3)-(1-3a)-4a=3a

We move all terms to the left:

(2a+3)-(1-3a)-4a-(3a)=0

We add all the numbers together, and all the variables

(2a+3)-(-3a+1)-4a-3a=0

We add all the numbers together, and all the variables

-7a+(2a+3)-(-3a+1)=0

We get rid of parentheses

-7a+2a+3a+3-1=0

We add all the numbers together, and all the variables

-2a+2=0

We move all terms containing a to the left, all other terms to the right

-2a=-2

a=-2/-2

a=1

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