(2a+3)/5=(a+1)/3

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Solution for (2a+3)/5=(a+1)/3 equation: 



(2a+3)/5=(a+1)/3

We move all terms to the left:

(2a+3)/5-((a+1)/3)=0

We calculate fractions


2a/()+(-((a+1)*5)/()=0



We calculate terms in parentheses: +(-((a+1)*5)/(), so:

-((a+1)*5)/(

We multiply all the terms by the denominator


-((a+1)*5)



We calculate terms in parentheses: -((a+1)*5), so:

(a+1)*5

We multiply parentheses

5a+5

Back to the equation:

-(5a+5)



We get rid of parentheses

-5a-5

Back to the equation:

+(-5a-5)



We get rid of parentheses

2a/()-5a-5=0

We multiply all the terms by the denominator


2a-5a*()-5*()=0

We add all the numbers together, and all the variables

2a-5a*()=0

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