(2a+3)/5=7a

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Solution for (2a+3)/5=7a equation: 



(2a+3)/5=7a

We move all terms to the left:

(2a+3)/5-(7a)=0

We add all the numbers together, and all the variables

-7a+(2a+3)/5=0

We multiply all the terms by the denominator


-7a*5+(2a+3)=0

Wy multiply elements

-35a+(2a+3)=0

We get rid of parentheses

-35a+2a+3=0

We add all the numbers together, and all the variables

-33a+3=0

We move all terms containing a to the left, all other terms to the right

-33a=-3

a=-3/-33

a=1/11

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