(2a+3)/7=(3a)/6

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Solution for (2a+3)/7=(3a)/6 equation: 


a in (-oo:+oo)

(2*a+3)/7 = (3*a)/6 // - (3*a)/6

(2*a+3)/7-((3*a)/6) = 0

(2*a+3)/7+(-1/2)*a = 0

(2*a+3)/7-a/2 = 0

(2*(2*a+3))/(2*7)+(7*(-a))/(2*7) = 0

2*(2*a+3)+7*(-a) = 0

6-3*a = 0

(6-3*a)/(2*7) = 0

(6-3*a)/(2*7) = 0 // * 2*7

6-3*a = 0

6-3*a = 0 // - 6

-3*a = -6 // : -3

a = -6/(-3)

a = 2

a = 2

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