(2a+3b+4c)+(4a+2b)=

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Solution for (2a+3b+4c)+(4a+2b)= equation:


Simplifying
(2a + 3b + 4c) + (4a + 2b) = 0

Remove parenthesis around (2a + 3b + 4c)
2a + 3b + 4c + (4a + 2b) = 0

Remove parenthesis around (4a + 2b)
2a + 3b + 4c + 4a + 2b = 0

Reorder the terms:
2a + 4a + 3b + 2b + 4c = 0

Combine like terms: 2a + 4a = 6a
6a + 3b + 2b + 4c = 0

Combine like terms: 3b + 2b = 5b
6a + 5b + 4c = 0

Solving
6a + 5b + 4c = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-5b' to each side of the equation.
6a + 5b + -5b + 4c = 0 + -5b

Combine like terms: 5b + -5b = 0
6a + 0 + 4c = 0 + -5b
6a + 4c = 0 + -5b
Remove the zero:
6a + 4c = -5b

Add '-4c' to each side of the equation.
6a + 4c + -4c = -5b + -4c

Combine like terms: 4c + -4c = 0
6a + 0 = -5b + -4c
6a = -5b + -4c

Divide each side by '6'.
a = -0.8333333333b + -0.6666666667c

Simplifying
a = -0.8333333333b + -0.6666666667c

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