(2a+3b+c)+(a+3b+-4c)=

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Solution for (2a+3b+c)+(a+3b+-4c)= equation:


Simplifying
(2a + 3b + c) + (a + 3b + -4c) = 0

Remove parenthesis around (2a + 3b + c)
2a + 3b + c + (a + 3b + -4c) = 0

Remove parenthesis around (a + 3b + -4c)
2a + 3b + c + a + 3b + -4c = 0

Reorder the terms:
2a + a + 3b + 3b + c + -4c = 0

Combine like terms: 2a + a = 3a
3a + 3b + 3b + c + -4c = 0

Combine like terms: 3b + 3b = 6b
3a + 6b + c + -4c = 0

Combine like terms: c + -4c = -3c
3a + 6b + -3c = 0

Solving
3a + 6b + -3c = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-6b' to each side of the equation.
3a + 6b + -6b + -3c = 0 + -6b

Combine like terms: 6b + -6b = 0
3a + 0 + -3c = 0 + -6b
3a + -3c = 0 + -6b
Remove the zero:
3a + -3c = -6b

Add '3c' to each side of the equation.
3a + -3c + 3c = -6b + 3c

Combine like terms: -3c + 3c = 0
3a + 0 = -6b + 3c
3a = -6b + 3c

Divide each side by '3'.
a = -2b + c

Simplifying
a = -2b + c

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