(2a-3)(3a-1)-(6a+2)(a-5)=30

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Solution for (2a-3)(3a-1)-(6a+2)(a-5)=30 equation:



(2a-3)(3a-1)-(6a+2)(a-5)=30
We move all terms to the left:
(2a-3)(3a-1)-(6a+2)(a-5)-(30)=0
We multiply parentheses ..
(+6a^2-2a-9a+3)-(6a+2)(a-5)-30=0
We get rid of parentheses
6a^2-2a-9a-(6a+2)(a-5)+3-30=0
We multiply parentheses ..
6a^2-(+6a^2-30a+2a-10)-2a-9a+3-30=0
We add all the numbers together, and all the variables
6a^2-(+6a^2-30a+2a-10)-11a-27=0
We get rid of parentheses
6a^2-6a^2+30a-2a-11a+10-27=0
We add all the numbers together, and all the variables
17a-17=0
We move all terms containing a to the left, all other terms to the right
17a=17
a=17/17
a=1

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