(2a-3)-(4+5a)=-5-2(a+3)

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Solution for (2a-3)-(4+5a)=-5-2(a+3) equation: 



(2a-3)-(4+5a)=-5-2(a+3)

We move all terms to the left:

(2a-3)-(4+5a)-(-5-2(a+3))=0

We add all the numbers together, and all the variables

(2a-3)-(5a+4)-(-5-2(a+3))=0

We get rid of parentheses

2a-5a-(-5-2(a+3))-3-4=0



We calculate terms in parentheses: -(-5-2(a+3)), so:

-5-2(a+3)

determiningTheFunctionDomain
-2(a+3)-5

We multiply parentheses

-2a-6-5

We add all the numbers together, and all the variables

-2a-11

Back to the equation:

-(-2a-11)



We add all the numbers together, and all the variables

-3a-(-2a-11)-7=0

We get rid of parentheses

-3a+2a+11-7=0

We add all the numbers together, and all the variables

-1a+4=0

We move all terms containing a to the left, all other terms to the right

-a=-4

a=-4/-1

a=+4

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