(2a-3b+4c)-(-a+3b+4c)=

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Solution for (2a-3b+4c)-(-a+3b+4c)= equation:


Simplifying
(2a + -3b + 4c) + -1(-1a + 3b + 4c) = 0

Remove parenthesis around (2a + -3b + 4c)
2a + -3b + 4c + -1(-1a + 3b + 4c) = 0
2a + -3b + 4c + (-1a * -1 + 3b * -1 + 4c * -1) = 0
2a + -3b + 4c + (1a + -3b + -4c) = 0

Reorder the terms:
2a + 1a + -3b + -3b + 4c + -4c = 0

Combine like terms: 2a + 1a = 3a
3a + -3b + -3b + 4c + -4c = 0

Combine like terms: -3b + -3b = -6b
3a + -6b + 4c + -4c = 0

Combine like terms: 4c + -4c = 0
3a + -6b + 0 = 0
3a + -6b = 0

Solving
3a + -6b = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '6b' to each side of the equation.
3a + -6b + 6b = 0 + 6b

Combine like terms: -6b + 6b = 0
3a + 0 = 0 + 6b
3a = 0 + 6b
Remove the zero:
3a = 6b

Divide each side by '3'.
a = 2b

Simplifying
a = 2b

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