(2a-4)+2(a-5)-3(a+1)=

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Solution for (2a-4)+2(a-5)-3(a+1)= equation:


Simplifying
(2a + -4) + 2(a + -5) + -3(a + 1) = 0

Reorder the terms:
(-4 + 2a) + 2(a + -5) + -3(a + 1) = 0

Remove parenthesis around (-4 + 2a)
-4 + 2a + 2(a + -5) + -3(a + 1) = 0

Reorder the terms:
-4 + 2a + 2(-5 + a) + -3(a + 1) = 0
-4 + 2a + (-5 * 2 + a * 2) + -3(a + 1) = 0
-4 + 2a + (-10 + 2a) + -3(a + 1) = 0

Reorder the terms:
-4 + 2a + -10 + 2a + -3(1 + a) = 0
-4 + 2a + -10 + 2a + (1 * -3 + a * -3) = 0
-4 + 2a + -10 + 2a + (-3 + -3a) = 0

Reorder the terms:
-4 + -10 + -3 + 2a + 2a + -3a = 0

Combine like terms: -4 + -10 = -14
-14 + -3 + 2a + 2a + -3a = 0

Combine like terms: -14 + -3 = -17
-17 + 2a + 2a + -3a = 0

Combine like terms: 2a + 2a = 4a
-17 + 4a + -3a = 0

Combine like terms: 4a + -3a = 1a
-17 + 1a = 0

Solving
-17 + 1a = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '17' to each side of the equation.
-17 + 17 + 1a = 0 + 17

Combine like terms: -17 + 17 = 0
0 + 1a = 0 + 17
1a = 0 + 17

Combine like terms: 0 + 17 = 17
1a = 17

Divide each side by '1'.
a = 17

Simplifying
a = 17

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