(2a-4)+2(a-5)=3(a+1)

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Solution for (2a-4)+2(a-5)=3(a+1) equation: 



(2a-4)+2(a-5)=3(a+1)

We move all terms to the left:

(2a-4)+2(a-5)-(3(a+1))=0

We multiply parentheses

(2a-4)+2a-(3(a+1))-10=0

We get rid of parentheses

2a+2a-(3(a+1))-4-10=0



We calculate terms in parentheses: -(3(a+1)), so:

3(a+1)

We multiply parentheses

3a+3

Back to the equation:

-(3a+3)



We add all the numbers together, and all the variables

4a-(3a+3)-14=0

We get rid of parentheses

4a-3a-3-14=0

We add all the numbers together, and all the variables

a-17=0

We move all terms containing a to the left, all other terms to the right

a=17

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