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(2a-6)=4a-(2a-12)
We move all terms to the left:
(2a-6)-(4a-(2a-12))=0
We get rid of parentheses
2a-(4a-(2a-12))-6=0
We calculate terms in parentheses: -(4a-(2a-12)), so:We get rid of parentheses
4a-(2a-12)
We get rid of parentheses
4a-2a+12
We add all the numbers together, and all the variables
2a+12
Back to the equation:
-(2a+12)
2a-2a-12-6=0
We add all the numbers together, and all the variables
-18!=0
There is no solution for this equation
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