(2a-7/5)+5=2a

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Solution for (2a-7/5)+5=2a equation: 


a in (-oo:+oo)

2*a-(7/5)+5 = 2*a // - 2*a

2*a-(2*a)-(7/5)+5 = 0

2*a-2*a-7/5+5 = 0

18/5 = 0

a belongs to the empty set

a belongs to the empty set

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