(2a-b+3c)+(a+5b-4c)=

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Solution for (2a-b+3c)+(a+5b-4c)= equation:


Simplifying
(2a + -1b + 3c) + (a + 5b + -4c) = 0

Remove parenthesis around (2a + -1b + 3c)
2a + -1b + 3c + (a + 5b + -4c) = 0

Remove parenthesis around (a + 5b + -4c)
2a + -1b + 3c + a + 5b + -4c = 0

Reorder the terms:
2a + a + -1b + 5b + 3c + -4c = 0

Combine like terms: 2a + a = 3a
3a + -1b + 5b + 3c + -4c = 0

Combine like terms: -1b + 5b = 4b
3a + 4b + 3c + -4c = 0

Combine like terms: 3c + -4c = -1c
3a + 4b + -1c = 0

Solving
3a + 4b + -1c = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-4b' to each side of the equation.
3a + 4b + -4b + -1c = 0 + -4b

Combine like terms: 4b + -4b = 0
3a + 0 + -1c = 0 + -4b
3a + -1c = 0 + -4b
Remove the zero:
3a + -1c = -4b

Add 'c' to each side of the equation.
3a + -1c + c = -4b + c

Combine like terms: -1c + c = 0
3a + 0 = -4b + c
3a = -4b + c

Divide each side by '3'.
a = -1.333333333b + 0.3333333333c

Simplifying
a = -1.333333333b + 0.3333333333c

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