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(2a/7)=(2/3)
We move all terms to the left:
(2a/7)-((2/3))=0
We add all the numbers together, and all the variables
(+2a/7)-((+2/3))=0
We get rid of parentheses
2a/7-((+2/3))=0
We calculate fractions
6a^2/()+()/()=0
We add all the numbers together, and all the variables
6a^2/()+1=0
We multiply all the terms by the denominator
6a^2+1*()=0
We add all the numbers together, and all the variables
6a^2=0
a = 6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$a=\frac{-b}{2a}=\frac{0}{12}=0$
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