(2a/x+1)+b=(2b/x+1)+a

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Solution for (2a/x+1)+b=(2b/x+1)+a equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(2*a)/x+b+1 = a+(2*b)/x+1 // - a+(2*b)/x+1

(2*a)/x-a+b-((2*b)/x)-1+1 = 0

(2*a)/x-a+b-2*b*x^-1-1+1 = 0

2*a*x^-1-a+b-2*b*x^-1 = 0

t_1 = x^-1

b-a+2*a*t_1^1-2*b*t_1^1 = 0

b-a-2*b*t_1 = 0 // - b-a

-2*b*t_1 = -(b-a) // : -2*b

t_1 = (-(b-a))/(-2*b)

t_1 = (a-b)/(-2*b)

t_1 = (a-b)/(-2*b)

x^-1-((a-b)/(-2*b)) = 0

(-1*(a-b))/(-2*b)+1/x = 0

(-1*x*(a-b))/(-2*b*x)+(-2*1*b)/(-2*b*x) = 0

-1*x*(a-b)-2*1*b = 0

b*x-(a*x)-2*b = 0

b*x-(a*x)-2*b = 0

b*x-2*b = 0 // + -2*b

b*x = -(-2*b) // : b

x = (-(-2*b))/b

x = 2

x-2 = 0

(x-2)/(-2*b*x) = 0

(x-2)/(-2*b*x) = 0 // * -2*b*x

x-2 = 0

x-2 = 0 // + 2

x = 2

x = 2

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