(2ab+3c)(2ab-3c)=

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Solution for (2ab+3c)(2ab-3c)= equation:


Simplifying
(2ab + 3c)(2ab + -3c) = 0

Multiply (2ab + 3c) * (2ab + -3c)
(2ab * (2ab + -3c) + 3c * (2ab + -3c)) = 0
((2ab * 2ab + -3c * 2ab) + 3c * (2ab + -3c)) = 0

Reorder the terms:
((-6abc + 4a2b2) + 3c * (2ab + -3c)) = 0
((-6abc + 4a2b2) + 3c * (2ab + -3c)) = 0
(-6abc + 4a2b2 + (2ab * 3c + -3c * 3c)) = 0
(-6abc + 4a2b2 + (6abc + -9c2)) = 0

Reorder the terms:
(-6abc + 6abc + 4a2b2 + -9c2) = 0

Combine like terms: -6abc + 6abc = 0
(0 + 4a2b2 + -9c2) = 0
(4a2b2 + -9c2) = 0

Solving
4a2b2 + -9c2 = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '9c2' to each side of the equation.
4a2b2 + -9c2 + 9c2 = 0 + 9c2

Combine like terms: -9c2 + 9c2 = 0
4a2b2 + 0 = 0 + 9c2
4a2b2 = 0 + 9c2
Remove the zero:
4a2b2 = 9c2

Divide each side by '4b2'.
a2 = 2.25b-2c2

Simplifying
a2 = 2.25b-2c2

Take the square root of each side:
a = {-1.5b-1c, 1.5b-1c}

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