(2b)x(2bc+3c)=

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Solution for (2b)x(2bc+3c)= equation:


Simplifying
(2b) * x(2bc + 3c) = 0

Remove parenthesis around (2b)
2b * x(2bc + 3c) = 0

Multiply b * x
2bx(2bc + 3c) = 0
(2bc * 2bx + 3c * 2bx) = 0

Reorder the terms:
(6bcx + 4b2cx) = 0
(6bcx + 4b2cx) = 0

Solving
6bcx + 4b2cx = 0

Solving for variable 'b'.

Factor out the Greatest Common Factor (GCF), '2bcx'.
2bcx(3 + 2b) = 0

Ignore the factor 2.

Subproblem 1

Set the factor 'bcx' equal to zero and attempt to solve: Simplifying bcx = 0 Solving bcx = 0 Move all terms containing b to the left, all other terms to the right. Simplifying bcx = 0 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined.

Subproblem 2

Set the factor '(3 + 2b)' equal to zero and attempt to solve: Simplifying 3 + 2b = 0 Solving 3 + 2b = 0 Move all terms containing b to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + 2b = 0 + -3 Combine like terms: 3 + -3 = 0 0 + 2b = 0 + -3 2b = 0 + -3 Combine like terms: 0 + -3 = -3 2b = -3 Divide each side by '2'. b = -1.5 Simplifying b = -1.5

Solution

b = {-1.5}

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