(2b+1)(2b-1)=

Solution for (2b+1)(2b-1)= equation:

Simplifying
(2b + 1)(2b + -1) = 0

Reorder the terms:
(1 + 2b)(2b + -1) = 0

Reorder the terms:
(1 + 2b)(-1 + 2b) = 0

Multiply (1 + 2b) * (-1 + 2b)
(1(-1 + 2b) + 2b * (-1 + 2b)) = 0
((-1 * 1 + 2b * 1) + 2b * (-1 + 2b)) = 0
((-1 + 2b) + 2b * (-1 + 2b)) = 0
(-1 + 2b + (-1 * 2b + 2b * 2b)) = 0
(-1 + 2b + (-2b + 4b2)) = 0

Combine like terms: 2b + -2b = 0
(-1 + 0 + 4b2) = 0
(-1 + 4b2) = 0

Solving
-1 + 4b2 = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + 4b2 = 0 + 1

Combine like terms: -1 + 1 = 0
0 + 4b2 = 0 + 1
4b2 = 0 + 1

Combine like terms: 0 + 1 = 1
4b2 = 1

Divide each side by '4'.
b2 = 0.25

Simplifying
b2 = 0.25

Take the square root of each side:
b = {-0.5, 0.5}