(2b+19/5)-9=3b

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Solution for (2b+19/5)-9=3b equation:



(2b+19/5)-9=3b
We move all terms to the left:
(2b+19/5)-9-(3b)=0
We add all the numbers together, and all the variables
(+2b+19/5)-3b-9=0
We add all the numbers together, and all the variables
-3b+(+2b+19/5)-9=0
We get rid of parentheses
-3b+2b-9+19/5=0
We multiply all the terms by the denominator
-3b*5+2b*5+19-9*5=0
We add all the numbers together, and all the variables
-3b*5+2b*5-26=0
Wy multiply elements
-15b+10b-26=0
We add all the numbers together, and all the variables
-5b-26=0
We move all terms containing b to the left, all other terms to the right
-5b=26
b=26/-5
b=-5+1/5

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