(2b+3)-(4b-5)=6

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Solution for (2b+3)-(4b-5)=6 equation: 



(2b+3)-(4b-5)=6

We move all terms to the left:

(2b+3)-(4b-5)-(6)=0

We get rid of parentheses

2b-4b+3+5-6=0

We add all the numbers together, and all the variables

-2b+2=0

We move all terms containing b to the left, all other terms to the right

-2b=-2

b=-2/-2

b=1

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