(2b+4)(2b-4)=

Solution for (2b+4)(2b-4)= equation:

Simplifying
(2b + 4)(2b + -4) = 0

Reorder the terms:
(4 + 2b)(2b + -4) = 0

Reorder the terms:
(4 + 2b)(-4 + 2b) = 0

Multiply (4 + 2b) * (-4 + 2b)
(4(-4 + 2b) + 2b * (-4 + 2b)) = 0
((-4 * 4 + 2b * 4) + 2b * (-4 + 2b)) = 0
((-16 + 8b) + 2b * (-4 + 2b)) = 0
(-16 + 8b + (-4 * 2b + 2b * 2b)) = 0
(-16 + 8b + (-8b + 4b2)) = 0

Combine like terms: 8b + -8b = 0
(-16 + 0 + 4b2) = 0
(-16 + 4b2) = 0

Solving
-16 + 4b2 = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '16' to each side of the equation.
-16 + 16 + 4b2 = 0 + 16

Combine like terms: -16 + 16 = 0
0 + 4b2 = 0 + 16
4b2 = 0 + 16

Combine like terms: 0 + 16 = 16
4b2 = 16

Divide each side by '4'.
b2 = 4

Simplifying
b2 = 4

Take the square root of each side:
b = {-2, 2}