(2b+5)=(3b-2)

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Solution for (2b+5)=(3b-2) equation: 



(2b+5)=(3b-2)

We move all terms to the left:

(2b+5)-((3b-2))=0

We get rid of parentheses

2b-((3b-2))+5=0



We calculate terms in parentheses: -((3b-2)), so:

(3b-2)

We get rid of parentheses

3b-2

Back to the equation:

-(3b-2)



We get rid of parentheses

2b-3b+2+5=0

We add all the numbers together, and all the variables

-1b+7=0

We move all terms containing b to the left, all other terms to the right

-b=-7

b=-7/-1

b=+7

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