(2b-1)/5=(b-2)/15

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Solution for (2b-1)/5=(b-2)/15 equation: 


b in (-oo:+oo)

(2*b-1)/5 = (b-2)/15 // - (b-2)/15

(2*b-1)/5-((b-2)/15) = 0

(2*b-1)/5+(-1*(b-2))/15 = 0

(15*(2*b-1))/(5*15)+(-1*5*(b-2))/(5*15) = 0

15*(2*b-1)-1*5*(b-2) = 0

25*b-5 = 0

(25*b-5)/(5*15) = 0

(25*b-5)/(5*15) = 0 // * 5*15

25*b-5 = 0

25*b-5 = 0 // + 5

25*b = 5 // : 25

b = 5/25

b = 1/5

b = 1/5

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