(2b-10)+(3b-6)=15b-60

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Solution for (2b-10)+(3b-6)=15b-60 equation: 



(2b-10)+(3b-6)=15b-60

We move all terms to the left:

(2b-10)+(3b-6)-(15b-60)=0

We get rid of parentheses

2b+3b-15b-10-6+60=0

We add all the numbers together, and all the variables

-10b+44=0

We move all terms containing b to the left, all other terms to the right

-10b=-44

b=-44/-10

b=4+2/5

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