(2b-2)9=3(b-1)

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Solution for (2b-2)9=3(b-1) equation: 



(2b-2)9=3(b-1)

We move all terms to the left:

(2b-2)9-(3(b-1))=0

We multiply parentheses

18b-(3(b-1))-18=0



We calculate terms in parentheses: -(3(b-1)), so:

3(b-1)

We multiply parentheses

3b-3

Back to the equation:

-(3b-3)



We get rid of parentheses

18b-3b+3-18=0

We add all the numbers together, and all the variables

15b-15=0

We move all terms containing b to the left, all other terms to the right

15b=15

b=15/15

b=1

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